Difficulty: Easy
Correct Answer: A capacitance in parallel with the series combination of a resistance and an inductance
Explanation:
Introduction / Context:
No physical inductor is ideal. Winding resistance and interwinding capacitance alter behavior at both low and high frequencies. A suitable equivalent circuit helps predict resonances, Q factor, and losses—critical in filters, RF chokes, and switch-mode power supplies.
Given Data / Assumptions:
Concept / Approach:
A common small-signal model is L in series with R_s, representing copper loss, with a shunt (parallel) capacitance C_p modeling self-capacitance between turns or layers. This topology exhibits a self-resonant frequency where the inductive reactance and capacitive reactance cancel, beyond which the inductor can appear capacitive. Such a model matches measured impedance-versus-frequency curves for practical components.
Step-by-Step Solution:
Verification / Alternative check:
Impedance analyzers reveal a peak and phase crossover at the self-resonant frequency, predicted by the R_s–L series branch shunted by C_p.
Why Other Options Are Wrong:
Common Pitfalls:
Neglecting C_p at high frequency, leading to incorrect assumptions that inductors stay inductive across all frequencies.
Final Answer:
A capacitance in parallel with the series combination of a resistance and an inductance
Discussion & Comments