Difficulty: Easy
Correct Answer: passing of the higher frequencies
Explanation:
Introduction / Context:
First-order RL networks are foundational building blocks in analog electronics. Whether the output is taken across the resistor or the inductor changes the filter's behavior. Understanding this helps in predicting Bode plots, time-domain response, and in designing simple tone controls or sensor front ends.
Given Data / Assumptions:
Concept / Approach:
The inductor's reactance is XL = 2 * π * f * L, which increases with frequency. In a series path, the voltage division is frequency dependent: V_L / V_in = XL / sqrt(R^2 + XL^2). At low f, XL is small, so most input appears across R (little across L). At high f, XL dominates, so most input appears across L. Therefore, with output taken across L, higher frequencies are passed better than lower ones—this is a high-pass characteristic (first order).
Step-by-Step Solution:
Verification / Alternative check:
Plot the magnitude response: the -3 dB cutoff occurs near f_c = R / (2 * π * L). Frequency sweep measurements will show increasing output with frequency when probing across the inductor.
Why Other Options Are Wrong:
Common Pitfalls:
Mixing up where the output is taken; swapping L and R or moving the probe changes the apparent filter type.
Final Answer:
passing of the higher frequencies
Discussion & Comments