Difficulty: Easy
Correct Answer: TM10
Explanation:
Introduction:Rectangular waveguides support a family of discrete transverse electric (TE) and transverse magnetic (TM) modes. The allowed indices depend on boundary conditions. Recognizing which index combinations are valid is essential for mode charts, cutoff calculations, and avoiding spurious propagation in microwave hardware.
Given Data / Assumptions:
Concept / Approach:
For TE modes, at least one index must be nonzero (m, n not both zero). That allows index combinations such as TE10, TE01, TE11, etc. For TM modes, both indices must be nonzero because a TM mode requires both transverse variations to satisfy boundary conditions with Ez ≠ 0 and Hz = 0. Therefore, TMm0 or TM0n do not exist as propagating modes.
Step-by-Step Solution:
1) Evaluate TE candidates: TE15 and TE12 are valid TE modes (m or n may be zero, but here both are nonzero anyway).2) Evaluate TM candidates: TM11 is valid since both indices are nonzero.3) TM10 has n = 0 → violates TM existence condition.4) Conclude TM10 cannot propagate in a hollow rectangular guide.Verification / Alternative check:
Standard tables list TEmn for m,n ≥ 0 with not both zero; TMmn for m,n ≥ 1—confirming that TM10 is disallowed.
Why Other Options Are Wrong:
TE15, TE12, TE01, and TM11 are all permissible modes (though their cutoffs differ).
Common Pitfalls:
Assuming TM modes are allowed with a zero index like TE; they are not.
Final Answer:
TM10.
Discussion & Comments