Difficulty: Easy
Correct Answer: Hydrophobic interactions
Explanation:
Introduction:Several interactions stabilize the native state of proteins. This question targets the principal favorable driver that pushes nonpolar residues into the core and shapes the overall fold in aqueous environments.
Given Data / Assumptions:
Concept / Approach:The hydrophobic effect is largely entropic from the solvent perspective. Aggregating nonpolar surfaces reduces the structured water shell, releasing water molecules to the bulk and increasing solvent entropy, which strongly favors folding. Other forces such as hydrogen bonds and van der Waals contacts refine the fold and add stability but are often compensatory because similar interactions exist in the unfolded state with water.
Step-by-Step Solution:
1) Consider the unfolded state: nonpolar side chains are hydrated, imposing ordered water shells.2) Upon folding, nonpolar surfaces bury against each other, decreasing total nonpolar surface exposed to water.3) This releases ordered water and increases solvent entropy, lowering free energy significantly.4) Hydrogen bonds and van der Waals interactions contribute, but their net gain can be modest compared to the hydrophobic effect because the unfolded chain also forms hydrogen bonds with water.Verification / Alternative check:Mutational studies show that substituting hydrophobic core residues with polar or smaller residues often destabilizes the fold more than disrupting individual hydrogen bonds, highlighting the dominant role of hydrophobic burial.
Why Other Options Are Wrong:
Common Pitfalls:Equating hydrogen bonding with the main folding driver. Hydrogen bonds are essential for secondary structure but the hydrophobic effect largely powers the global collapse.
Final Answer:Hydrophobic interactions.
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