Which of the following is always odd?
Aptitude
Number System
Difficulty: Easy
Choose an option
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ASum of two odd numbers
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BDifference of two odd numbers
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CProduct of two odd numbers
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DNone of these
Answer
Correct Answer: Product of two odd numbers
Explanation
### Concept & Logic
The behavior of odd and even numbers under basic arithmetic operations follows strict parity rules. Understanding these foundational rules allows you to eliminate incorrect operations immediately.
### Step-by-Step Solution
**Given:**
* We need to find the operation between two odd numbers that always results in an odd number.
**Calculation / Deduction:**
Let's evaluate each arithmetic operation:
* **Option (a) Sum:** When you add two odd numbers, the "extra" units pair up to form an even number. (e.g., $3 + 5 = 8$). Always even.
* **Option (b) Difference:** Subtracting an odd number from another odd number removes the "oddness", leaving an even result. (e.g., $7 - 3 = 4$). Always even.
* **Option (c) Product:** An odd number has no factors of 2. Multiplying two numbers with no factors of 2 results in a product that also has no factors of 2. (e.g., $3 \times 5 = 15$). Always odd.
### Exam Strategy & Shortcut
Whenever a question asks "which of the following is always [even/odd]", bypass mental abstractions and quickly plug in small prime numbers like $3$ and $5$.
Sum: $3+5=8$ (Even).
Difference: $5-3=2$ (Even).
Product: $3 \times 5=15$ (Odd).
Option (c) is the only one that yields an odd result. This technique takes 3 seconds.
### Common Pitfall
A standard trap is overthinking the generalized algebra, such as testing $(2k+1)(2m+1) = 4km + 2k + 2m + 1$, when a simple numerical substitution is far faster and less prone to algebraic errors under exam pressure.
### Final Answer
Therefore, the correct answer is **Product of two odd numbers**.