Difficulty: Easy
Correct Answer: Fluorine
Explanation:
Introduction / Context:
Oxidation state is a useful concept in inorganic chemistry that indicates the apparent charge an atom would have if all bonds were ionic. Many elements can exhibit multiple oxidation states in different compounds. However, a few elements tend to show only one oxidation state in their compounds due to their extreme electronegativity or other factors. This question asks you to identify the element that effectively has the same oxidation state in all of its compounds.
Given Data / Assumptions:
Concept / Approach:
Fluorine is the most electronegative element in the periodic table. In compounds, it always attracts electrons more strongly than any other element. As a result, fluorine virtually always has an oxidation state of minus one in its compounds, because it gains one electron relative to its neutral atom. Hydrogen can be plus one in most compounds and minus one in metal hydrides, so it does not have a single oxidation state. Oxygen is usually minus two but can be minus one in peroxides and also positive states in compounds with fluorine. Carbon shows a wide range of oxidation states from minus four to plus four. Therefore, fluorine is the only element among these that maintains the same oxidation state in all its compounds.
Step-by-Step Solution:
Step 1: Recall that fluorine is the most electronegative element and tends to gain one electron in bonds.
Step 2: Therefore, in almost all of its compounds, fluorine has an oxidation state of minus one.
Step 3: Consider hydrogen, which typically has an oxidation state of plus one when bonded to non metals but minus one in metal hydrides such as sodium hydride.
Step 4: Consider oxygen, which usually has oxidation state minus two, but in peroxides such as hydrogen peroxide it has minus one, and in compounds with fluorine it can have positive oxidation states.
Step 5: Note that carbon has many oxidation states in organic and inorganic compounds, ranging from minus four up to plus four, so it clearly does not have a constant oxidation state. Thus, fluorine is the correct answer.
Verification / Alternative check:
List some common compounds for each element. Fluorine appears in hydrogen fluoride (oxidation state minus one), sodium fluoride (minus one), and many organic fluorides where it is also minus one. There are no stable compounds in which fluorine has a positive oxidation state because no other element exceeds its electronegativity. Hydrogen appears as plus one in HCl, H2O, and NH3, but as minus one in NaH and CaH2. Oxygen is minus two in H2O and most oxides, minus one in H2O2, and plus two in OF2. Carbon varies widely, for example minus four in methane, zero in elemental carbon, and plus four in carbon dioxide. These examples confirm that only fluorine is fixed at minus one in all its compounds.
Why Other Options Are Wrong:
Hydrogen does not have a single oxidation state because in metal hydrides it is clearly in the minus one state, while in acids and many other compounds it is plus one. Carbon can have many oxidation states depending on its bonding environment, so it is very flexible and cannot be said to have one fixed oxidation state. Oxygen is usually minus two but has notable exceptions such as peroxides and compounds with fluorine where its oxidation state is different. Therefore, these elements do not meet the requirement of having the same oxidation state in all their compounds.
Common Pitfalls:
A common error is to choose oxygen because students remember that oxygen is almost always minus two. However, examination questions often test awareness of the exceptions, especially in peroxides and compounds like OF2. Another mistake is to choose hydrogen, forgetting that metal hydrides exist. To avoid these pitfalls, remember the simple rule that fluorine is the most electronegative element and therefore always has oxidation state minus one in its compounds.
Final Answer:
Among the given elements, fluorine has essentially the same oxidation state of minus one in all of its compounds.
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