Difficulty: Easy
Correct Answer: DNA polymerase I
Explanation:
Introduction:During bacterial DNA replication, short RNA primers synthesized by primase must be removed and replaced with DNA. Recognizing the enzyme responsible for primer removal is essential for understanding lagging-strand processing and Okazaki fragment maturation.
Given Data / Assumptions:
Concept / Approach:E. coli DNA polymerase I possesses a unique 5'→3' exonuclease activity that removes RNA primers while simultaneously filling the resulting gaps with DNA (nick translation). DNA polymerase III is the main replicative enzyme but lacks the 5'→3' exonuclease for primer removal. DNA ligase subsequently seals remaining nicks by forming phosphodiester bonds.
Step-by-Step Solution:
Primase lays down RNA primers on both strands (especially frequent on lagging strand).DNA pol III extends primers, creating Okazaki fragments.DNA pol I uses 5'→3' exonuclease to remove RNA primer nucleotides.DNA pol I fills in with DNA using its polymerase activity.DNA ligase joins adjacent fragments by sealing the nick.Verification / Alternative check:Mutants lacking DNA pol I 5'→3' exonuclease activity accumulate RNA primers and unprocessed Okazaki fragments, confirming the enzyme's specialized role in primer removal and gap filling.
Why Other Options Are Wrong:
Common Pitfalls:Assuming the main replicative polymerase (pol III) also removes primers; in bacteria, primer removal is a distinct function of pol I.
Final Answer:DNA polymerase I
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