Difficulty: Easy
Correct Answer: Exonuclease activity (3'→5' proofreading)
Explanation:
Introduction:The Klenow fragment is a large proteolytic fragment of E. coli DNA polymerase I that retains the polymerase and 3'→5' exonuclease domains but lacks the 5'→3' exonuclease domain. Understanding its retained activities is essential for its use in cloning, labeling, and blunt-end polishing.
Given Data / Assumptions:
Concept / Approach:Without available dNTP substrates, Klenow cannot extend DNA strands, but it can still remove mismatched or terminal nucleotides via its proofreading exonuclease. This property allows limited trimming or quality control of DNA ends even when synthesis cannot proceed.
Step-by-Step Solution:
Recognize domain composition of Klenow: polymerase + 3'→5' exonuclease.Remove dNTPs from the reaction: polymerase activity is halted.Remaining function: 3'→5' exonuclease can excise nucleotides from the 3' end.Conclusion: Klenow exhibits exonuclease activity without free nucleotides.Verification / Alternative check:Biochemical assays show degradation of mismatched 3' termini by Klenow in nucleotide-free conditions, demonstrating persistent proofreading capability independent of synthesis.
Why Other Options Are Wrong:
Common Pitfalls:Confusing 5'→3' exonuclease (absent in Klenow) with 3'→5' proofreading (retained), or assuming all polymerase-associated activities require dNTPs.
Final Answer:Exonuclease activity (3'→5' proofreading)
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