Difficulty: Easy
Correct Answer: Class A
Explanation:
Introduction / Context:Classful addressing divides IP addresses into Classes A, B, C, D, and E. Understanding the default number of host addresses available in each class is a fundamental networking concept for historical IP addressing schemes and subnetting.
Given Data / Assumptions:
Concept / Approach:
Class A networks use an 8-bit network prefix and a 24-bit host portion, providing 2^24 – 2 usable host addresses (about 16.7 million). Class B provides 65,534 hosts, Class C provides 254 hosts. Therefore, Class A has the most hosts by default.
Step-by-Step Solution:
Class A: 2^24 – 2 = 16,777,214 hosts.Class B: 2^16 – 2 = 65,534 hosts.Class C: 2^8 – 2 = 254 hosts.Thus, Class A has the largest number of default hosts.Verification / Alternative check:
Textbook IP addressing tables confirm these values.
Why Other Options Are Wrong:
Common Pitfalls:
Final Answer:
Class A
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