IP address classes Which class of IP address provides the largest number of host addresses by default (before subnetting is applied)?

Difficulty: Easy

Correct Answer: Class A

Explanation:


Introduction / Context:
Classful addressing divides IP addresses into Classes A, B, C, D, and E. Understanding the default number of host addresses available in each class is a fundamental networking concept for historical IP addressing schemes and subnetting.


Given Data / Assumptions:

  • We are considering traditional classful addressing, not CIDR (Classless Inter-Domain Routing).
  • Host availability is determined before subnetting.
  • Class D is reserved for multicast, Class E for experimental use.


Concept / Approach:

Class A networks use an 8-bit network prefix and a 24-bit host portion, providing 2^24 – 2 usable host addresses (about 16.7 million). Class B provides 65,534 hosts, Class C provides 254 hosts. Therefore, Class A has the most hosts by default.


Step-by-Step Solution:

Class A: 2^24 – 2 = 16,777,214 hosts.Class B: 2^16 – 2 = 65,534 hosts.Class C: 2^8 – 2 = 254 hosts.Thus, Class A has the largest number of default hosts.


Verification / Alternative check:

Textbook IP addressing tables confirm these values.


Why Other Options Are Wrong:

  • Class B and C: significantly fewer hosts.
  • A and B combined: classes are not combined in addressing.
  • Class D: reserved for multicast, not hosts.


Common Pitfalls:

  • Forgetting to subtract 2 for network and broadcast addresses.
  • Confusing CIDR notation with classful addressing.


Final Answer:

Class A

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