C#.NET — What will the corrected program print? (Assume the intended method name is fun1, not funl.) namespace CuriousTabConsoleApplication { class SampleProgram { static void Main(string[] args) { int i = 5; int j; fun1(ref i); fun2(out j); Console.WriteLine(i + ", " + j); } static void fun1(ref int x) { x = x * x; } static void fun2(out int x) { x = 6; x = x * x; } } }

Difficulty: Medium

Correct Answer: 25, 36

Explanation:


Introduction / Context:
The original snippet contains a likely typographical error: fun1 is called but funl is defined. Assuming the intended name is fun1, this question examines ref and out semantics and arithmetic updates.



Given Data / Assumptions:

  • i starts at 5 and is passed by ref to fun1.
  • j is declared unassigned and passed as out to fun2.
  • fun1 squares its argument; fun2 sets x = 6 and then squares it.


Concept / Approach:
ref passes an existing variable for in-place modification. out requires assignment inside the method before use. After both calls, Console.WriteLine prints the final values.



Step-by-Step Solution:

fun1(ref i): i becomes 5 * 5 = 25.fun2(out j): j is set to 6, then j becomes 6 * 6 = 36.WriteLine prints "25, 36".


Verification / Alternative check:
Trace variable states after each call or run an equivalent small program.



Why Other Options Are Wrong:

  • 5, 6 / 5, 36 / 25, 0 / 5, 0: Each misses one of the squaring operations or misapplies ref/out behavior.


Common Pitfalls:
Overlooking the typo and concluding a compile error; the conceptual goal is to assess ref/out effects.



Final Answer:
25, 36

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