Ribosome composition in bacteria What are the Svedberg sedimentation values of the two subunits that compose the 70S ribosome of Escherichia coli?
-
A40S and 30S
-
B50S and 20S
-
C50S and 30S
-
D40S and 20S
-
E60S and 40S
Answer
Correct Answer: 50S and 30S
Explanation
Introduction / Context:Prokaryotic ribosomes are termed 70S, composed of two unequal subunits whose sizes are crucial to antibiotic targeting, translation initiation, and molecular biology techniques. Recognizing the subunit S values helps differentiate bacterial from eukaryotic ribosomes (80S with 60S/40S subunits).
Given Data / Assumptions:
- Bacterial ribosome overall: 70S (sedimentation coefficient, not additive).
- Goal: identify the pair of subunit S values for E. coli.
- Standard growth conditions and wild-type ribosomes assumed.
Concept / Approach:
The prokaryotic ribosome comprises a large 50S subunit (containing 23S and 5S rRNAs with proteins) and a small 30S subunit (16S rRNA with proteins). The combined particle is 70S due to non-linear sedimentation properties; Svedberg units are not strictly additive.
Step-by-Step Solution:
Recall standard bacterial ribosomal subunits: 50S large, 30S small.Confirm that 50S + 30S assemble into the 70S ribosome.Select 50S and 30S.Verification / Alternative check:
Textbook diagrams and antibiotic mechanisms (e.g., macrolides binding 50S, aminoglycosides targeting 30S) corroborate the subunit identities and sizes.
Why Other Options Are Wrong:
- 40S/30S or 40S/20S: Mixed or nonstandard values; 40S is eukaryotic small subunit.
- 50S/20S: No 20S bacterial subunit exists.
- 60S/40S: Eukaryotic ribosome (80S), not bacterial.
Common Pitfalls:
- Assuming Svedberg units add linearly; they do not due to shape/mass/friction effects.
Final Answer:
50S and 30S