Preset pattern for a ring counter What preset condition is required for a ring shift counter before clocking begins?

Difficulty: Easy

Correct Answer: a single 1, the rest 0

Explanation:


Introduction / Context:
A ring counter is a shift register with its serial output fed back to the serial input. It cycles a single active bit through its stages, generating one-hot codes widely used in sequencing and timing applications.


Given Data / Assumptions:

  • Ring counter built from n flip-flops.
  • Feedback is direct (not inverted), so the active state is 1.
  • We want proper operation immediately after preset.


Concept / Approach:

For a direct ring counter, the valid circulating pattern is one-hot: exactly one stage = 1 and all others = 0. Each clock shifts the 1 into the next flip-flop. Presetting all 1s or all 0s would stall the counter; a single 0 with the rest 1 would circulate zeros, not the intended one-hot 1.


Step-by-Step Solution:

Preset Q0..Q(n−1) such that one chosen stage is 1 and all others are 0.On each clock, the 1 advances by one stage.After n clocks, the pattern repeats.


Verification / Alternative check:

Waveforms of ring counters show the single 1 stepping through outputs; alternative preset patterns fail to produce the canonical sequence.


Why Other Options Are Wrong:

  • All 1s or all 0s: no single active bit to circulate.
  • Single 0, rest 1: describes an inverted (0-hot) behavior, not the standard ring counter.


Common Pitfalls:

  • Confusing ring counters with Johnson counters, which use inverted feedback and produce 2n states.


Final Answer:

a single 1, the rest 0

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