Directions: Study the table carefully and answer the given questions. Total exports of six countries over five years (in ₹ crore) | Years $\rightarrow$
Country $\downarrow$ | 1998 | 1999 | 2000 | 2001 | 2002 | | :--- | :--- | :--- | :--- | :--- | :--- | | P | 20 | 40 | 60 | 45 | 90 | | Q | 30 | 25 | 15 | 50 | 100 | | R | 50 | 55 | 70 | 90 | 65 | | S | 45 | 60 | 20 | 15 | 25 | | T | 60 | 50 | 55 | 100 | 110 | | U | 24 | 40 | 60 | 75 | 120 | Note: Profit = Exports – Imports By what per cent is the average export of country T over all the given years more than the average export of country R over all the given years?

Aptitude Statistics Difficulty: Hard
Choose an option
  • A
    $13\frac{7}{11}$%
  • B
    $9\frac{1}{11}$%
  • C
    $13\frac{5}{7}$%
  • D
    $4\frac{7}{11}$%
  • E
    $12\frac{1}{7}$%

Answer

Correct Answer: $13\frac{7}{11}$%

Explanation

### Concept & Averages Calculate the average of a dataset by dividing the total sum by the number of observations. Then, find the percentage difference between two averages. $$ \text{Percentage Difference} = \frac{\text{Difference}}{\text{Base Value}} \times 100 $$ ### Step-by-Step Solution 1. **Calculate average export for T:** - Total = $60 + 50 + 55 + 100 + 110 = 375$. - Average = $\frac{375}{5} = 75$. 2. **Calculate average export for R:** - Total = $50 + 55 + 70 + 90 + 65 = 330$. - Average = $\frac{330}{5} = 66$. 3. **Find the percentage difference:** We need how much T is *more than* R, so R is the base. - Difference = $75 - 66 = 9$. - Percentage = $\left(\frac{9}{66}\right) \times 100 = \frac{3}{22} \times 100 = \frac{150}{11}\%$. 4. **Convert to mixed fraction:** $\frac{150}{11} = 13\frac{7}{11}\%$. ### Exam Strategy & Shortcut Instead of finding averages first, find the difference in the sums: $375 - 330 = 45$. Divide by 5 to find the average difference: $9$. Then calculate $\frac{9}{66} \times 100$. This saves an extra division step. ### Common Pitfall Using the wrong base for the percentage calculation. Since the question asks "more than the average export of R", R's average ($66$) must be the denominator. ### Final Answer Therefore, the correct answer is **$13\frac{7}{11}$%**.
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