Impedance magnitude of a series RC at 3 kHz: A 0.22 µF capacitor is in series with a 200 Ω resistor and connected to a 3 kHz sinusoidal source. What is the magnitude of the total impedance |Z|?

Difficulty: Medium

Correct Answer: 313 Ω

Explanation:


Introduction:
In a series RC circuit, impedance is the vector sum of resistance and capacitive reactance. The magnitude determines current for a given applied voltage and frequency, which is key in filter and timing applications.


Given Data / Assumptions:

  • R = 200 Ω
  • C = 0.22 µF
  • f = 3 kHz
  • Series connection, ideal components


Concept / Approach:

Compute capacitive reactance Xc = 1 / (2 * π * f * C). Then the impedance magnitude is |Z| = sqrt(R^2 + Xc^2).


Step-by-Step Solution:

Xc = 1 / (2 * π * 3000 * 0.22e-6) ≈ 241 Ω|Z| = sqrt(200^2 + 241^2) Ω|Z| ≈ sqrt(40000 + 58081) = sqrt(98081) ≈ 313 Ω


Verification / Alternative check:

Since R and Xc are comparable (200 Ω vs 241 Ω), |Z| must exceed each but be less than their sum; 313 Ω satisfies this bound (200 < 313 < 441).


Why Other Options Are Wrong:

  • 214 Ω: Less than R; impossible for magnitude with additional reactance.
  • 414 Ω and 880 Ω: Overestimates; closer to linear addition, not vector.
  • 241 Ω: This is Xc alone, not the total magnitude.


Common Pitfalls:

  • Adding R and Xc arithmetically instead of vectorially.
  • Using wrong units for C (µF vs F).


Final Answer:

313 Ω

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