Impedance magnitude of a series RC at 3 kHz: A 0.22 µF capacitor is in series with a 200 Ω resistor and connected to a 3 kHz sinusoidal source. What is the magnitude of the total impedance |Z|?
Electronics
Capacitors
Difficulty: Medium
Choose an option
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A214 Ω
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B313 Ω
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C414 Ω
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D880 Ω
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E241 Ω
Answer
Correct Answer: 313 Ω
Explanation
Introduction:In a series RC circuit, impedance is the vector sum of resistance and capacitive reactance. The magnitude determines current for a given applied voltage and frequency, which is key in filter and timing applications.
Given Data / Assumptions:
- R = 200 Ω
- C = 0.22 µF
- f = 3 kHz
- Series connection, ideal components
Concept / Approach:
Compute capacitive reactance Xc = 1 / (2 * π * f * C). Then the impedance magnitude is |Z| = sqrt(R^2 + Xc^2).
Step-by-Step Solution:
Xc = 1 / (2 * π * 3000 * 0.22e-6) ≈ 241 Ω|Z| = sqrt(200^2 + 241^2) Ω|Z| ≈ sqrt(40000 + 58081) = sqrt(98081) ≈ 313 ΩVerification / Alternative check:
Since R and Xc are comparable (200 Ω vs 241 Ω), |Z| must exceed each but be less than their sum; 313 Ω satisfies this bound (200 < 313 < 441).
Why Other Options Are Wrong:
- 214 Ω: Less than R; impossible for magnitude with additional reactance.
- 414 Ω and 880 Ω: Overestimates; closer to linear addition, not vector.
- 241 Ω: This is Xc alone, not the total magnitude.
Common Pitfalls:
- Adding R and Xc arithmetically instead of vectorially.
- Using wrong units for C (µF vs F).
Final Answer:
313 Ω