Recombinant DNA technology: Which enzyme catalyzes formation of covalent phosphodiester bonds to join compatible restriction fragments?
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ADNA primase
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BDNA helicase
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CDNA polymerase
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DDNA ligase
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ETopoisomerase I
Answer
Correct Answer: DNA ligase
Explanation
Introduction:After restriction enzymes generate compatible DNA ends, the fragments must be covalently joined to create a continuous backbone. The enzyme responsible for sealing the nick between adjacent nucleotides is a mainstay of cloning workflows. This question asks you to identify that enzyme—DNA ligase.
Given Data / Assumptions:
- Restriction digestion produces either sticky (cohesive) or blunt ends.
- Annealing of sticky ends relies on base pairing but remains a nicked backbone until sealed.
- Cloning requires stable covalent joins for propagation in cells.
Concept / Approach:DNA ligase catalyzes formation of a phosphodiester bond between adjacent 3′-OH and 5′-phosphate termini. T4 DNA ligase uses ATP, whereas E. coli DNA ligase uses NAD+. Ligation can join both cohesive and blunt ends (the latter typically at lower efficiency), enabling insert–vector assembly in plasmids and other constructs.
Step-by-Step Solution:
Generate compatible ends via restriction digestion or end-repair.Allow complementary overhangs to anneal if present.Add DNA ligase with appropriate buffer and cofactors (ATP or NAD+).Ligase seals the nicks, creating a continuous phosphodiester backbone.Verification / Alternative check:Successful ligation yields transformants with intact plasmids; control reactions lacking ligase fail to produce stable constructs, demonstrating the necessity of covalent sealing.
Why Other Options Are Wrong:
- Primase synthesizes RNA primers; helicase unwinds duplexes; polymerase extends DNA but does not seal nicks; topoisomerase alters supercoiling and can transiently break/rejoin strands but is not used for cloning ligation.
Common Pitfalls:Assuming annealed sticky ends are permanently joined without ligase; base pairing alone is insufficient for stable propagation.
Final Answer:DNA ligase