Masonry design: for a free-standing masonry wall (unsupported at the top and restrained only at the base), what effective height should be used when computing slenderness ratio?

Civil Engineering UPSC Civil Service Exam Questions Difficulty: Easy
Choose an option
  • A
    0.5 L
  • B
    1.0 L
  • C
    2.0 L
  • D
    2.5 L
  • E
    1.5 L

Answer

Correct Answer: 2.0 L

Explanation

Introduction / Context:Slenderness effects significantly influence the compressive capacity of masonry walls. Codes use an effective height (or length) to account for end restraint conditions. A free-standing wall behaves like a cantilever with one end fixed and the other free, increasing the effective height compared to a wall braced at both ends.

Given Data / Assumptions:

  • Wall is free-standing (top unrestrained laterally).
  • Base is effectively fixed at foundation level.
  • Effective height is used in slenderness ratio λ = effective_height / effective_thickness.

Concept / Approach:For column/strut analogues, the effective length factors depend on end restraints: fixed–free members have an effective length of 2.0 L (twice the clear height). This increases slenderness and reduces allowable stress to reflect the higher propensity for buckling or instability.

Step-by-Step Solution:Recognize end conditions: fixed at base, free at top.Use standard effective length factor K = 2.0 for fixed–free condition.Therefore, effective height = K * L = 2.0 L.

Verification / Alternative check:Structural design handbooks and masonry codes list effective height multipliers; fixed–free consistently corresponds to 2.0.

Why Other Options Are Wrong:

  • 0.5 L and 1.0 L reflect braced conditions with more restraint than present.
  • 2.5 L overstates the cantilever effect beyond standard practice.

Common Pitfalls:Assuming the top has some bracing when it is explicitly free; using clear height directly without effective length factor.

Final Answer:2.0 L

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