Difficulty: Easy
Correct Answer: 2.0 L
Explanation:
Introduction / Context:
Slenderness effects significantly influence the compressive capacity of masonry walls. Codes use an effective height (or length) to account for end restraint conditions. A free-standing wall behaves like a cantilever with one end fixed and the other free, increasing the effective height compared to a wall braced at both ends.
Given Data / Assumptions:
Concept / Approach:
For column/strut analogues, the effective length factors depend on end restraints: fixed–free members have an effective length of 2.0 L (twice the clear height). This increases slenderness and reduces allowable stress to reflect the higher propensity for buckling or instability.
Step-by-Step Solution:
Recognize end conditions: fixed at base, free at top.Use standard effective length factor K = 2.0 for fixed–free condition.Therefore, effective height = K * L = 2.0 L.
Verification / Alternative check:
Structural design handbooks and masonry codes list effective height multipliers; fixed–free consistently corresponds to 2.0.
Why Other Options Are Wrong:
Common Pitfalls:
Assuming the top has some bracing when it is explicitly free; using clear height directly without effective length factor.
Final Answer:
2.0 L
Discussion & Comments