In microwave networks, a uniform waveguide section behaves like which type of filter around its cutoff?

Electronics and Communication Engineering Microwave Communication Difficulty: Easy
Choose an option
  • A
    Low-pass filter
  • B
    Band-pass filter
  • C
    High-pass filter
  • D
    Band-stop (notch) filter
  • E
    All-pass network

Answer

Correct Answer: High-pass filter

Explanation

Introduction / Context:Metallic waveguides support propagation only above their cutoff frequency. Below cutoff, fields are evanescent and power does not propagate. This frequency-selective behavior mirrors a classic filter response in RF design.

Given Data / Assumptions:

  • Uniform rectangular or circular waveguide section.
  • Single-mode region around the dominant mode cutoff.
  • Losses assumed small compared with cutoff effects.

Concept / Approach:

For a given mode, the propagation constant β is real for f > fc and imaginary for f < fc. Thus, the section 'passes' energy above fc and 'blocks' it below fc, which is the hallmark of a high-pass filter behavior.

Step-by-Step Solution:

Identify dominant mode with cutoff fc.For f < fc: β becomes imaginary; fields decay exponentially → no transmission.For f > fc: β is real; power propagates → transmission occurs.Therefore, the waveguide section functions as a high-pass filter.

Verification / Alternative check:

Plotting S21 versus frequency for an ideal waveguide shows near-zero transmission below fc and increasing transmission above fc, matching a high-pass characteristic.

Why Other Options Are Wrong:

  • Low-pass: Opposite of waveguide behavior.
  • Band-pass / Band-stop: Would require two edges; a simple uniform guide exhibits a single cutoff edge.
  • All-pass: Not true; magnitude and phase vary strongly around cutoff.

Common Pitfalls:

Confusing cavity resonators (band-pass) with uniform guides; overlooking that mode conversion or discontinuities can create additional filtering not present in a straight section.

Final Answer:

High-pass filter

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