Difficulty: Easy
Correct Answer: newtonian
Explanation:
Introduction:
Fluids can be classified by rheology (stress–strain-rate behavior) and by idealization versus reality. The question asks specifically for rheological classification, focusing on the relation between shear stress and shear rate.
Given Data / Assumptions:
Concept / Approach:
A Newtonian fluid obeys tau = mu * (du/dy), where tau is shear stress and du/dy is shear rate, with constant dynamic viscosity mu independent of shear rate. Water closely follows this linear law across wide shear rates, making it Newtonian. An ideal (inviscid) fluid is a mathematical abstraction and not physically realizable for water; non-Newtonian fluids exhibit shear-dependent viscosity or yield stress, which water does not in normal conditions.
Step-by-Step Solution:
Identify the requested basis: rheology, not idealization.Recall the Newtonian constitutive equation tau = mu * (du/dy) with mu approximately constant for water.Conclude that water is Newtonian.
Verification / Alternative check:
Experimental viscosity measurements show mu for water varies primarily with temperature, not shear rate, within engineering ranges—consistent with Newtonian behavior.
Why Other Options Are Wrong:
Real: true but not a rheological category by itself; the question seeks the stress–strain relation.Ideal: inviscid model; water is viscous.Non-Newtonian: would require shear-thinning/thickening or yield behavior absent in pure water.
Common Pitfalls:
Choosing “real” because it sounds correct; mixing modeling idealizations (ideal vs real) with rheological classes (Newtonian vs non-Newtonian).
Final Answer:
newtonian
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