Kinematic Viscosity from Poise and Specific Gravity An oil has specific gravity S = 0.95 and dynamic viscosity mu = 0.011 poise. What is its kinematic viscosity nu in stokes (1 stoke = 1 cm^2/s)?

Introduction:
In cgs units, dynamic viscosity is measured in poise and kinematic viscosity in stokes. They are related through fluid density. Quick conversions are common in lubrication problems and Reynolds number estimates.

Given Data / Assumptions:

• Specific gravity S = 0.95 ⇒ density rho = 0.95 g/cm^3.
• Dynamic viscosity mu = 0.011 poise.
• Temperature effects ignored; single-phase liquid.

Concept / Approach:
Kinematic viscosity is nu = mu / rho. In cgs, mu in poise and rho in g/cm^3 give nu directly in stokes (cm^2/s).

Step-by-Step Solution:
Compute rho from specific gravity: rho = S * 1 g/cm^3 = 0.95 g/cm^3.Apply nu = mu / rho = 0.011 / 0.95.Calculate value: 0.0115789… stokes ≈ 0.0116 stoke (rounded to 4 significant figures).

Verification / Alternative check:
Dimensional check: poise/(g/cm^3) = (g/(cm*s))/(g/cm^3) = cm^2/s = stoke. Magnitude is reasonable for light oils.

Why Other Options Are Wrong:
0.116 and 0.611 are an order of magnitude larger; 0.0611 is too high for the given numbers; only 0.0116 matches mu/rho.

Common Pitfalls:
Confusing SI and cgs; dividing by specific gravity incorrectly; rounding too early leading to noticeable error.

Final Answer:
0.0116 stoke