Coefficient of compressibility from e–σ′ change A soil sample’s void ratio decreases from 1.50 to 1.25 when the effective pressure increases from 25 t/m² to 50 t/m². Compute the coefficient of compressibility a_v (units: per t/m²).

Difficulty: Easy

Correct Answer: 0.01

Explanation:


Introduction / Context:
The coefficient of compressibility a_v is a one-dimensional parameter relating void ratio change to effective stress change within a pressure interval. It is used in settlement calculations and is distinct from the coefficient of volume compressibility m_v, which also includes division by (1 + e) for volumetric strain per unit stress.


Given Data / Assumptions:

  • Initial void ratio e1 = 1.50; final void ratio e2 = 1.25.
  • Initial σ′1 = 25 t/m²; final σ′2 = 50 t/m².
  • Use incremental definition over the given range.


Concept / Approach:

By definition (incremental form): a_v = Δe / Δσ′ with Δe taken as a positive number for a reduction in e under an increase in stress when reporting magnitude over an interval (sign conventions vary; many texts report the magnitude).


Step-by-Step Solution:

Δe = e1 − e2 = 1.50 − 1.25 = 0.25.Δσ′ = 50 − 25 = 25 t/m².a_v = 0.25 / 25 = 0.01 per t/m².


Verification / Alternative check:

If m_v were requested, m_v = a_v / (1 + e_avg); here only a_v is needed, matching the provided options.


Why Other Options Are Wrong:

0.02 or 0.05 overstate compressibility for the given changes; 0.001 and 0.10 are off by an order of magnitude.


Common Pitfalls:

Using the wrong stress difference; confusing a_v with m_v; sign confusion when e decreases with increasing σ′.


Final Answer:

0.01 per t/m²

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