Riboflavin (vitamin B2) behavior: The yellow pigment in egg yolk and milk becomes what on reduction with zinc in acid, and what upon re-oxidation?

Introduction / Context:Riboflavin (vitamin B2) forms flavin coenzymes (FMN, FAD) that are yellow due to their conjugated isoalloxazine ring. The color changes with oxidation state provide a simple chemical demonstration of redox behavior.

Given Data / Assumptions:

• Reduction performed with zinc in acidic solution.
• Observation of visible color changes tied to electronic structure.
• Re-oxidation occurs on exposure to air or oxidants.

Concept / Approach:Oxidized flavins are yellow; the fully reduced form (leucoflavin) is colorless. Thus, reduction bleaches the pigment; re-oxidation restores the yellow color by re-establishing the chromophore's conjugation.

Step-by-Step Solution:Start: oxidized riboflavin → yellow.Reduce with Zn/H+: riboflavin → leucoflavin (colorless).Expose to oxygen: leucoflavin → oxidized riboflavin (yellow returns).

Verification / Alternative check:Laboratory demonstrations and spectroscopic data show diminished absorbance in the visible range upon reduction, recovering on re-oxidation.

Why Other Options Are Wrong:

• Claiming colorless on oxidation reverses the real chemistry.
• Suggestions of deeper color on reduction are contrary to the bleaching effect of forming leucoflavin.

Common Pitfalls:Confusing semiquinone (blue/green radical) with fully reduced leucoflavin; complete reduction under the stated conditions yields colorless leuco species.

Final Answer:colorless on reduction with Zn in acid and regained its color on re-oxidation