Difficulty: Easy
Correct Answer: Oxidized and reduced form both
Explanation:
Introduction / Context:Lipoic acid (often as protein-bound lipoamide) is a swinging-arm redox cofactor in multienzyme complexes such as pyruvate dehydrogenase and α-ketoglutarate dehydrogenase. Appreciating its redox cycling explains how acyl-group transfer and electron transfer are coupled.
Given Data / Assumptions:
Concept / Approach:During catalysis, lipoamide cycles between an oxidized disulfide and a reduced dithiol. The reduced form accepts acyl groups and transfers reducing equivalents to FAD/NAD+, regenerating the oxidized form for subsequent catalytic rounds. Therefore, it exists in both oxidized and reduced states in vivo.
Step-by-Step Solution:
Oxidized lipoamide (S-S) is attached to E2 of the dehydrogenase complex.Reduction to dihydrolipoamide (SH, SH) occurs during acyl transfer from E1.Re-oxidation via E3 transfers electrons to FAD and then to NAD+, closing the redox loop.Thus both oxidation states are essential and interconvert during catalysis.Verification / Alternative check:Spectroscopic and structural studies of pyruvate dehydrogenase confirm lipoamide’s redox swing between disulfide and dithiol states with concurrent electron flow.
Why Other Options Are Wrong:
Common Pitfalls:Forgetting that lipoamide is covalently tethered to the enzyme and serves both as an acyl carrier and redox carrier, requiring both forms.
Final Answer:Oxidized and reduced form both
Discussion & Comments