Difficulty: Easy
Correct Answer: 1 centipoise
Explanation:
Introduction / Context:
Viscosity benchmarks enable quick checks of rheological calculations and pump sizing. Engineers often memorize a few anchor values, and water at room temperature is the most important of these.
Given Data / Assumptions:
Concept / Approach:
Water at ≈ 20°C has μ ≈ 1.0 mPa·s = 0.001 Pa·s. Since 1 P = 0.1 Pa·s and 1 cP = 0.001 Pa·s, water’s viscosity ≈ 1 cP. A poise (1 P) is 100× larger; a stoke (1 St) is a unit of kinematic viscosity, not dynamic.
Step-by-Step Solution:
Convert: 0.001 Pa·s → 1 cP (because 1 cP = 10^-3 Pa·s).Therefore, the closest standard value is 1 cP.
Verification / Alternative check:
At 20°C, tabulated μ_water ≈ 1.002 cP; at 25°C ≈ 0.89 cP. Both are of order unity in cP, confirming the benchmark.
Why Other Options Are Wrong:
1 P is too large; 1 St is not a dynamic viscosity; “both” mixes incompatible units; 10 cP corresponds to far more viscous liquids like light oils.
Common Pitfalls:
Confusing dynamic with kinematic viscosity and mixing poise with stoke without density conversion.
Final Answer:
1 centipoise
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