Difficulty: Easy
Correct Answer: x1/x2
Explanation:
Introduction / Context:
Mole fraction is a fundamental composition variable in thermodynamics and phase equilibria. For very dilute solutions, convenient approximations simplify calculations while maintaining acceptable accuracy. This question tests your ability to derive a first-order approximation for the mole fraction of solute when the solute amount is much smaller than the solvent amount.
Given Data / Assumptions:
Concept / Approach:
By definition, mole fraction of solute X_solute = x1 / (x1 + x2). Under the dilute condition x1 ≪ x2, the denominator x1 + x2 ≈ x2. Therefore X_solute ≈ x1/x2. This approximation is widely used to linearize expressions in mass transfer and colligative property estimations for trace solutes.
Step-by-Step Solution:
Verification / Alternative check:
Numerical example: x1 = 0.01, x2 = 100 → exact X = 0.01 / 100.01 ≈ 9.999e-5; approximate X ≈ 0.01 / 100 = 1.0e-4. Relative error is <0.001%.
Why Other Options Are Wrong:
B, D invert or distort the relationship. C approaches 1 and is nonsensical for a dilute solute. E is exact but the question asks for an approximate expression capturing the dilute simplification.
Common Pitfalls:
Applying the approximation outside the very dilute regime; forgetting that exact mole fraction is bounded between 0 and 1.
Final Answer:
x1/x2
Discussion & Comments