Corresponding states — Gases at the same reduced temperature (Tr) and reduced pressure (Pr) will exhibit which common behavior?

Difficulty: Easy

Correct Answer: both (a) and (b)

Explanation:


Introduction / Context:
The principle of corresponding states underpins generalized compressibility charts and equations of state. By normalizing temperature and pressure with respect to critical properties, many gases exhibit similar non-ideal behavior at the same reduced conditions. This allows engineers to estimate deviations from ideality without species-specific data for every case.


Given Data / Assumptions:

  • Reduced temperature Tr = T/Tc and reduced pressure Pr = P/Pc.
  • Gases are not in reactive mixtures; behavior is compared at identical Tr and Pr.
  • Acentric factor effects are modest (first-order corresponding states).


Concept / Approach:

At the same Tr and Pr, many gases show nearly the same compressibility factor Z. Similar Z implies a similar degree of deviation from ideal-gas behavior because Z quantifies PV/(nR*T). While exact equality is not guaranteed (acentric factor ω refines predictions), the “nearly same” behavior forms the basis of generalized charts and correlations.


Step-by-Step Solution:

Normalize conditions: compute Tr, Pr for each gas.Use generalized Z charts: at the same Tr, Pr, read Z values which cluster for many gases.Infer deviation from ideal gas: deviation ∝ |Z − 1| is similar among gases at same reduced conditions.Hence statements (a) and (b) are both valid.


Verification / Alternative check:

Comparisons across nitrogen, methane, and argon at identical Tr and Pr show comparable Z values, validating the principle, with small adjustments captured by ω in the Lee–Kesler method.


Why Other Options Are Wrong:

D rejects a well-founded principle. E concerns critical constants themselves, not reduced-condition behavior.


Common Pitfalls:

Using corresponding states near phase boundaries without caution; neglecting acentric factor corrections for polar or associating molecules.


Final Answer:

both (a) and (b)

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