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Two-destination ticket pricing: Solve simultaneous equations for fares to B and C. 2 tickets A→B + 3 tickets A→C cost Rs. 77. 3 tickets A→B + 2 tickets A→C cost Rs. 73. Find the individual fares from A to B and from A to C. Choose the correct ordered pair (B fare, C fare).

Q: Two-destination ticket pricing: Solve simultaneous equations for fares to B and C. 2 tickets A→B + 3 tickets A→C cost Rs. 77. 3 tickets A→B + 2 tickets A→C cost Rs. 73. Find the individual fares from A to B and from A to C. Choose the correct order…

Let fares be x = fare A→B y = fare A→C Form equations 2x + 3y = 77 … (1)3x + 2y = 73 … (2) Solve (1)×3 ⇒ 6x + 9y = 231(2)×2 ⇒ 6x + 4y = 146Subtract ⇒ 5y = 85 ⇒ y = 17.From (2): 3x + 2(17) = 73 ⇒ 3x = 39 ⇒ x = 13. Final Answer Rs. 13, Rs. 17