The value of $$\sqrt{\frac{(0.03)^2 + (0.21)^2 + (0.065)^2}{(0.003)^2 + (0.021)^2 + (0.0065)^2}}$$ is
Aptitude
Square Root and Cube Root
Difficulty: Medium
Choose an option
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A0.1
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B10
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C10^2
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D10^3
Answer
Correct Answer: 10
Explanation
### Concept & Formula
Express the terms in the denominator as a scaled version of the terms in the numerator by factoring out a common multiple of $10$.
### Step-by-Step Solution
Observe the relationship between the numbers in the numerator and the denominator:
* $0.003 = \frac{0.03}{10}$
* $0.021 = \frac{0.21}{10}$
* $0.0065 = \frac{0.065}{10}$
Substitute these relationships into the denominator:
$$\text{Denominator} = \left(\frac{0.03}{10}\right)^2 + \left(\frac{0.21}{10}\right)^2 + \left(\frac{0.065}{10}\right)^2$$
Factor out $\frac{1}{10^2}$ from the denominator:
$$\text{Denominator} = \frac{1}{10^2} \left[ (0.03)^2 + (0.21)^2 + (0.065)^2 \right]$$
Now substitute this back into the original square root expression:
$$\sqrt{\frac{(0.03)^2 + (0.21)^2 + (0.065)^2}{\frac{1}{10^2} \left[ (0.03)^2 + (0.21)^2 + (0.065)^2 \right]}}$$
Cancel out the common expression in both the numerator and denominator:
$$\sqrt{\frac{1}{\frac{1}{10^2}}} = \sqrt{10^2} = 10$$
### Exam Strategy & Shortcut
Every term in the denominator is exactly $\frac{1}{10}\text{th}$ of its corresponding term in the numerator. Since the terms are squared, the denominator is $\frac{1}{10^2} = \frac{1}{100}\text{th}$ of the numerator. Taking the square root of the reciprocal gives $\sqrt{100} = 10$ instantly.
### Common Pitfall
Students frequently choose $10^2$ (or $100$) by forgetting to take the final square root at the end of the simplification process. Always check the outermost operation!
### Final Answer
**Therefore, the correct answer is 10.**