Difficulty: Hard
Correct Answer: 3/4
Explanation:
Introduction / Context:
This problem looks intimidating, but it becomes clean once we convert the given square-root expression into simpler helper variables. It tests algebraic manipulation, squaring safely, and using identities like (p + q)^2 and (p - q)^2 to extract u and v type quantities.
Given Data / Assumptions:
Concept / Approach:
Introduce p and q as the two square-roots. Then rewrite u and v in terms of p and q. Finally compute (1 - a^2)(1 - b^2) = 1 - (a^2 + b^2) + a^2 b^2 = 1 - u + v^2.
Step-by-Step Solution:
Verification / Alternative check:
Notice the pq terms cancel completely, meaning the value is constant (independent of specific a and b) as long as the given condition holds.
Why Other Options Are Wrong:
Common Pitfalls:
Squaring without setting helper variables, mixing up u and v signs, or forgetting that (1 - a^2)(1 - b^2) = 1 - (a^2 + b^2) + a^2 b^2.
Final Answer:
3/4
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