In trigonometry, simplify and find the exact value of (cos 7A + cos 5A) / (sin 7A - sin 5A).

Difficulty: Medium

Correct Answer: cot A

Explanation:


Introduction / Context:
This question tests standard trigonometric sum-to-product identities. Expressions like cos C + cos D and sin C - sin D are designed so that the same common factor appears in numerator and denominator, allowing easy cancellation and producing a simple trig ratio (like tan or cot).


Given Data / Assumptions:

  • Expression: (cos 7A + cos 5A) / (sin 7A - sin 5A)
  • Use identities:
    • cos C + cos D = 2*cos((C + D)/2)*cos((C - D)/2)
    • sin C - sin D = 2*cos((C + D)/2)*sin((C - D)/2)


Concept / Approach:
Convert both numerator and denominator into product form and cancel the common factor 2*cos((C + D)/2). Then simplify to a basic trig ratio.


Step-by-Step Solution:

Step 1: Numerator: cos 7A + cos 5A = 2*cos((7A + 5A)/2)*cos((7A - 5A)/2). Step 2: That becomes 2*cos(6A)*cos(A). Step 3: Denominator: sin 7A - sin 5A = 2*cos((7A + 5A)/2)*sin((7A - 5A)/2). Step 4: That becomes 2*cos(6A)*sin(A). Step 5: Divide: (2*cos(6A)*cos(A)) / (2*cos(6A)*sin(A)). Step 6: Cancel 2*cos(6A): result = cos(A)/sin(A) = cot A.


Verification / Alternative check:
Pick A = 10 degrees (any valid value): both sum-to-product forms remain valid and cancellation always leads to cot A, confirming the simplification is identity-based, not numeric coincidence.


Why Other Options Are Wrong:

tan A: inverse of the correct ratio. tan 4A or cot 4A: would appear if the half-sum or half-difference were 4A, but here they are 6A and A. sec A: not a quotient of sin and cos directly here.


Common Pitfalls:
Using the wrong identity for sin C - sin D (it uses cos of half-sum, not sin), or mixing up half-sum and half-difference.


Final Answer:
cot A

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