Difficulty: Easy
Correct Answer: 2044000 kg/cm2
Explanation:
Introduction / Context:
Column buckling and allowable compressive stresses depend on the elastic modulus E of steel. Indian steel design in older working-stress formulations expresses E in kg/cm2, and a standardized value is used for routine calculations. This question asks for that numerical value in traditional units.
Given Data / Assumptions:
Concept / Approach:
Taking E ≈ 200–205 GPa for structural steel corresponds to about 2.0–2.05 × 10^6 kg/cm2. A commonly adopted value in Indian practice is ≈ 2.04 × 10^6 kg/cm2; in tabulations this appears as 2,044,000 kg/cm2 (2044000 kg/cm2).
Step-by-Step Solution:
Verification / Alternative check:
Using 2.04 × 10^6 kg/cm2 yields column buckling predictions consistent with code examples and design aids; small variations within 200–205 GPa do not materially affect preliminary sizing.
Why Other Options Are Wrong:
2,000,000 is slightly low; 2,045,000 and 2,047,000 are close but 2,044,000 is the standard rounded figure commonly cited in traditional tables.
Common Pitfalls:
Mixing SI units (MPa, GPa) with gravitational units (kg/cm2) mid-calculation, or using inconsistent E values across checks.
Final Answer:
2044000 kg/cm2
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