Moisture (water) content from wet and dry masses: An unsaturated soil sample (volume 100 cm³) weighs 190 g in the field. After oven drying, it weighs 160 g. What is the water content w of the soil?

Difficulty: Easy

Correct Answer: 0.188

Explanation:


Introduction / Context:
Water content (also called moisture content) is a fundamental index property in soil mechanics, needed for compaction control, shear strength correlations, and consolidation predictions. It compares the mass of water in a soil to the mass of dry soil solids.


Given Data / Assumptions:

  • Wet (natural) mass M_wet = 190 g.
  • Dry mass M_dry = 160 g (after oven drying).
  • Standard definition w = (mass of water) / (mass of dry solids).
  • Sample volume is provided but not required for w.


Concept / Approach:

Water content w is the ratio of the mass of water removed by drying to the mass of soil solids left after drying. It is commonly expressed as a decimal or percentage. Use simple subtraction to find water mass, then divide by dry mass.


Step-by-Step Solution:

Mass of water M_w = M_wet − M_dry = 190 − 160 = 30 g.Water content w = M_w / M_dry = 30 / 160 = 0.1875.Rounded to three decimals, w ≈ 0.188 (18.8%).


Verification / Alternative check:

A result under 0.20 is typical for an unsaturated compacted soil. If expressed in percent, w ≈ 18.8%.


Why Other Options Are Wrong:

0.288, 0.388, 0.488, and 0.588 imply much more water relative to solids than given by the mass difference.


Common Pitfalls:

Dividing by wet mass instead of dry mass, or forgetting to subtract to find water mass.


Final Answer:

0.188

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