Two-digit number with digit relation and reversal effect: The units digit is 1 less than twice the tens digit. After interchanging the digits, the difference (new − original) is 20 less than the original number. Find the original number.

Difficulty: Medium

Correct Answer: 47

Explanation:


Introduction / Context:
This problem combines a digit relationship with a condition on the difference between the reversed number and the original. Setting up algebra for digits and using the reversal difference formula make it tractable.


Given Data / Assumptions:

  • Tens digit = t; Units digit = u.
  • u = 2t − 1.
  • After swapping digits, difference (new − original) is less than the original by 20 ⇒ (new − original) = original − 20.


Concept / Approach:
Original = 10t + u; New = 10u + t. Then (new − original) = 9(u − t). Combine this with the linear relation u = 2t − 1 and the “less by 20” equation to solve for t.


Step-by-Step Solution:

new − original = 9(u − t)Given 9(u − t) = (10t + u) − 20Substitute u = 2t − 1 ⇒ 9((2t − 1) − t) = 10t + (2t − 1) − 209(t − 1) = 12t − 21 ⇒ 9t − 9 = 12t − 21 ⇒ 3t = 12 ⇒ t = 4u = 2*4 − 1 = 7 ⇒ Number = 47


Verification / Alternative check:
Reversed is 74. new − original = 74 − 47 = 27; original − 20 = 47 − 20 = 27. Condition holds exactly.


Why Other Options Are Wrong:

  • 59, 23, 35, 41: They fail either the digit relation u = 2t − 1 or the “difference” condition.


Common Pitfalls:
Misinterpreting “less than the original by 20” as subtracting 20 from the new number. Carefully equate (new − original) to (original − 20).


Final Answer:
47

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