Unit check for the Stefan–Boltzmann constant σ Select the correct SI unit for σ used in thermal radiation calculations.
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AW/m·K
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BW/m^2·K^2
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CW/m^2·K^4
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DW/m·K^2
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EJ/m^2·K
Answer
Correct Answer: W/m^2·K^4
Explanation
Introduction / Context:The Stefan–Boltzmann constant σ appears in the blackbody relation E_b = σ * T^4. Knowing σ’s units ensures dimensional consistency in radiation problems.
Given Data / Assumptions:
- Blackbody emissive power E_b has units W/m^2.
- Temperature is absolute (kelvin), denoted K.
Concept / Approach:Because E_b = σ * T^4 and E_b has units W/m^2, σ must carry units that when multiplied by K^4 yield W/m^2.
Step-by-Step Solution:Start with E_b units: W/m^2.T^4 units: K^4.Solve for σ units: (W/m^2) / K^4 = W/m^2·K^−4 = W/m^2·K^4 in denominator form.
Verification / Alternative check:Numerically, σ ≈ 5.6704 × 10^−8 W/m^2·K^4, consistent with standard references.
Why Other Options Are Wrong:
- W/m·K, W/m·K^2, W/m^2·K^2, J/m^2·K do not satisfy E_b = σ * T^4 dimensional balance.
Common Pitfalls:Mixing σ with convection coefficient h (W/m^2·K) or conduction constant k (W/m·K).
Final Answer:W/m^2·K^4