Difficulty: Easy
Correct Answer: N-s/m2
Explanation:
Introduction / Context:
Correct units are critical for dimensional checks and converting between property tables. Dynamic viscosity μ and kinematic viscosity ν often get mixed up due to the variety of unit systems used in practice (SI and CGS).
Given Data / Assumptions:
Concept / Approach:
From τ = μ * (du/dy), we get μ = τ / (du/dy). Therefore μ has units (N/m^2) / (s^-1) = N·s/m^2. In SI, this is also equal to Pa·s. CGS units define 1 poise = 0.1 Pa·s and 1 stoke = 1 cm^2/s for kinematic viscosity, not dynamic viscosity.
Step-by-Step Solution:
Start with τ in N/m^2 and du/dy in s^-1.Compute μ units: (N/m^2) / (s^-1) = N·s/m^2.Match this with the options → N-s/m2.
Verification / Alternative check:
Use ν = μ / ρ. If μ is N·s/m^2 and ρ is kg/m^3, then ν has units (N·s/m^2)/(kg/m^3) = (kg·m/s^2 * s / m^2) * (m^3/kg) = m^2/s, confirming consistency for kinematic viscosity units.
Why Other Options Are Wrong:
Common Pitfalls:
Final Answer:
N-s/m2
Discussion & Comments