Equivalent single pipe for a compound pipe Two pipes are said to be hydraulically equivalent when replacing a compound line by one new pipe. Choose the correct equivalence condition.

Difficulty: Easy

Correct Answer: loss of head and discharge of both the pipes is same

Explanation:


Introduction:
Pipeline design often replaces a series (compound) system with a single “equivalent” pipe for easier analysis. This question asks you to recall the precise criteria that define equivalence for head loss and flow rate.


Given Data / Assumptions:

  • Incompressible, steady flow.
  • Same fluid in both configurations.
  • Minor losses may be either included in the head loss accounting or neglected consistently.


Concept / Approach:
An equivalent pipe must transport the same discharge Q under the same total head loss H between the same endpoints as the original compound system. Matching Q ensures throughput equivalence; matching H ensures the same driving energy requirement. Length and diameter individually need not match; they adjust to meet the H–Q condition via friction relations (e.g., Darcy–Weisbach or Hazen–Williams).


Step-by-Step Solution:

1) Identify target variables to preserve: discharge Q and head loss H.2) Use a friction relation (e.g., H = f * (L/D) * (V^2 / (2g))) to select the equivalent L and D that yield the same H at the same Q.3) Conclude that equivalence means same head loss and same discharge.


Verification / Alternative check:
Hydraulic-grade line across endpoints remains unchanged if H and Q match, confirming energy and capacity equivalence.


Why Other Options Are Wrong:

  • Same length or diameter: not necessary individually.
  • Same head loss and velocity: equal velocity does not guarantee equal Q unless diameters also match.
  • Same Reynolds number: not required and may differ because D and V can change.


Common Pitfalls:
Over-focusing on geometric sameness rather than hydraulic performance (H–Q) equivalence.


Final Answer:
loss of head and discharge of both the pipes is same

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