Difficulty: Easy
Correct Answer: Acetyl-CoA
Explanation:
Introduction:
Aerobic carbohydrate metabolism channels the end product of glycolysis, pyruvate, into the mitochondrion for complete oxidation. This question tests your understanding of the pyruvate dehydrogenase (PDH) complex, the irreversible “gatekeeper” that converts pyruvate into a substrate suitable for the citric acid cycle.
Given Data / Assumptions:
Concept / Approach:
The PDH complex performs oxidative decarboxylation of pyruvate. It removes one carbon as CO2 and attaches the remaining two-carbon acetyl group to coenzyme A, forming acetyl-CoA. Electrons are transferred to NAD+ to yield NADH. This reaction is essentially irreversible in vivo and commits carbon to the TCA cycle and, potentially, fatty acid synthesis when energy is ample.
Step-by-Step Solution:
Verification / Alternative check:
PDH deficiency causes pyruvate and lactate accumulation and reduced acetyl-CoA formation, clinically validating that PDH’s product is acetyl-CoA used by the TCA cycle for ATP generation via oxidative phosphorylation.
Why Other Options Are Wrong:
Common Pitfalls:
Confusing PDH with pyruvate carboxylase or lactate dehydrogenase. Remember: PDH requires oxygen availability and generates acetyl-CoA plus NADH and CO2.
Final Answer:
Acetyl-CoA.
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