Difficulty: Medium
Correct Answer: Because gluconeogenesis must bypass the three irreversible glycolytic steps using ATP/GTP-consuming reactions
Explanation:
Introduction:
Although glycolysis and gluconeogenesis share many enzymes, they are not simple reversals of each other. This question probes the energetic asymmetry: why does synthesizing glucose de novo cost more high-energy phosphates than glycolysis yields when breaking it down?
Given Data / Assumptions:
Concept / Approach:
The irreversible steps in glycolysis are catalyzed by hexokinase/glucokinase (glucose → glucose-6-phosphate), phosphofructokinase-1 (fructose-6-phosphate → fructose-1,6-bisphosphate), and pyruvate kinase (phosphoenolpyruvate → pyruvate). Gluconeogenesis circumvents these with glucose-6-phosphatase, fructose-1,6-bisphosphatase, and the two-step pyruvate → oxaloacetate → PEP route (pyruvate carboxylase and PEP carboxykinase), consuming ATP and GTP to push the pathway uphill.
Step-by-Step Solution:
Verification / Alternative check:
Measured hepatocyte energetics show increased ATP/GTP consumption during fasting gluconeogenesis; hormonal regulation (glucagon elevating cAMP) coordinates substrate cycling and energy supply via fatty acid oxidation to pay the ATP cost.
Why Other Options Are Wrong:
Common Pitfalls:
Thinking of gluconeogenesis as a simple reversal of glycolysis; in reality, thermodynamics dictates distinct bypasses and an ATP/GTP investment.
Final Answer:
Because gluconeogenesis must bypass the three irreversible glycolytic steps using ATP/GTP-consuming reactions.
Discussion & Comments