Squares — Perimeter Comparison to Area Factor: The perimeters of two squares are 12 cm and 24 cm. The area of the larger square is how many times the area of the smaller square?

Difficulty: Easy

Correct Answer: 4 times

Explanation:


Introduction / Context:
Square perimeter is proportional to side length, and area scales with the square of side length. Doubling the perimeter doubles the side; the area therefore quadruples. This item reinforces the linear–quadratic linkage between perimeter and area.



Given Data / Assumptions:

  • P1 = 12 cm, P2 = 24 cm
  • Perimeter P = 4s ⇒ s = P/4
  • Area A = s^2


Concept / Approach:
Compute sides from perimeters, then compare areas. Because s2/s1 equals P2/P1, area ratio equals (P2/P1)^2. Here P2/P1 = 2, so area ratio = 4 : 1 (larger : smaller).



Step-by-Step Solution:

s1 = 12/4 = 3 cm; A1 = 9 cm^2.s2 = 24/4 = 6 cm; A2 = 36 cm^2.A2/A1 = 36/9 = 4.


Verification / Alternative check:

Using ratio method: (P2/P1)^2 = (24/12)^2 = 2^2 = 4.


Why Other Options Are Wrong:

  • 2 or 3 times ignores quadratic scaling.
  • 5 or 6 times overestimates the effect.


Common Pitfalls:

  • Mistaking a linear doubling for an area doubling.


Final Answer:
4 times.

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