Capacitance per unit length of a coaxial cable Two coaxial metallic cylinders have inner radius R1 and outer radius R2. The space between them is uniformly filled with a dielectric of relative permittivity εr. What is the capacitance per metre length?

Difficulty: Medium

Correct Answer: C′ = 2 * π * ε0 * εr / ln(R2 / R1)

Explanation:


Introduction / Context:
The capacitance per unit length of a coaxial line is a staple result in electromagnetics and transmission line theory. It follows from Gauss’s law under cylindrical symmetry with a homogeneous dielectric between the conductors.


Given Data / Assumptions:

  • Inner conductor radius R1, outer conductor inner radius R2 (R2 > R1).
  • Dielectric is linear, homogeneous, isotropic with permittivity ε = ε0 * εr.
  • Length considered is 1 metre (per-unit-length capacitance C′).


Concept / Approach:

Use Gauss’s law in integral form over a cylindrical surface to find the electric field E(r). Integrate the potential difference V between R1 and R2. The per-unit-length capacitance is C′ = Q / V for a 1 m length. The result contains a logarithm due to the 1/r dependence of E in cylindrical coordinates.


Step-by-Step Solution:

Choose Gaussian surface of radius r, length 1 m: ∮ D · dA = Q_free ⇒ D_r * (2 * π * r * 1) = Q ⇒ D_r = Q / (2 * π * r).Relate fields: D = εE ⇒ E(r) = D_r / ε = Q / (2 * π * ε * r).Potential: V = ∫_{R1}^{R2} E(r) dr = Q / (2 * π * ε) * ln(R2 / R1).Capacitance per metre: C′ = Q / V = 2 * π * ε / ln(R2 / R1) = 2 * π * ε0 * εr / ln(R2 / R1).


Verification / Alternative check:

Dimensional analysis: ε has units F/m; logarithm is dimensionless; result has units F/m as required. For εr = 1, this reduces to the vacuum formula.


Why Other Options Are Wrong:

  • Halving the numerator (π instead of 2π) underestimates C′ by 2.
  • Multiplying by ln instead of dividing reverses the dependence.
  • Using (R2 − R1) ignores cylindrical field variation (not a parallel-plate capacitor).


Common Pitfalls:

Confusing natural log with log base 10; forgetting ε = ε0 * εr; using diameter rather than radius.


Final Answer:

C′ = 2 * π * ε0 * εr / ln(R2 / R1)

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