Tuning a parallel resonant circuit: To shift the resonant frequency to a higher value, how should the capacitance be adjusted?

Introduction / Context:Tuning resonant circuits (LC tanks) is central in communication systems and filters. The resonant frequency depends on L and C, and understanding how each parameter affects frequency enables practical tuning.

Given Data / Assumptions:

• Parallel resonant LC circuit (losses neglected for the concept).
• Goal: increase resonant frequency f0.
• Inductance L held fixed; only C is adjusted.

Concept / Approach:

The resonance formula is f0 = 1 / (2 * π * √(L * C)). For fixed L, f0 varies inversely with √C. Therefore, reducing C increases f0; increasing C lowers f0.

Step-by-Step Solution:

Verification / Alternative check:

Example: If C is reduced by a factor of 4, √C halves and f0 doubles, illustrating the inverse-square-root relationship.

Why Other Options Are Wrong:

Increasing C decreases f0. Leaving C unchanged does not shift frequency. Replacing C with an inductor changes the topology rather than tuning it upward.

Common Pitfalls:

Confusing series vs. parallel resonance; thinking f0 is inversely proportional to C (it is inversely proportional to √C).

Final Answer:

decreased