Difficulty: Medium
Correct Answer: up
Explanation:
Introduction / Context:The operating point (Q-point) of a transistor is where the device resides on its load line under quiescent (no-signal) conditions. Understanding how changes in current gain affect this point is essential for bias stability and linear amplifier design.
Given Data / Assumptions:
Concept / Approach:Collector current Ic ≈ beta * Ib (for a given base current Ib). If beta rises while Ib is constant, Ic increases. On a load line (defined by Vcc and RC), higher Ic moves the Q-point toward higher current and lower collector-emitter voltage, i.e., up the current axis toward saturation.
Step-by-Step Solution:
1) Assume fixed Ib due to fixed bias network.2) Increase beta → Ic increases (Ic = beta * Ib).3) On the load line, larger Ic corresponds to a point higher on the vertical axis.4) Hence Q moves up (toward saturation), away from cutoff.Verification / Alternative check:Graphically, draw the same load line and intersect it with the new Ic for the unchanged base current; the intersection is above the previous Q-point.
Why Other Options Are Wrong:
Down: Would imply reduced Ic, opposite to an increase in beta.Nowhere: Ignores the dependence Ic = beta * Ib.Off the load line: DC operation must remain on the load line defined by Vcc and RC unless supply or RC changes.Common Pitfalls:Assuming feedback or emitter degeneration compensates automatically; without such stabilization, beta shifts do move the Q-point.
Final Answer:up.
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