Tour-budget linear equation (extend by 4 days, daily spend falls by ₹3): A traveler has a total budget of ₹360 for daily expenses. He extends the tour by 4 days, which reduces his daily spending by ₹3. Find the original planned number of tour days.

Difficulty: Medium

Correct Answer: 20

Explanation:


Introduction / Context:
This problem turns a budget scenario into a linear equation in the number of days. The total spend is fixed, so daily expense equals 360 divided by the number of days. Extending the tour reduces daily spend by a known amount, giving an equation to solve.


Given Data / Assumptions:

  • Total budget = ₹360
  • Original days = n → daily spend = 360 / n
  • Extended days = n + 4 → new daily spend = 360 / (n + 4)
  • New daily spend = old daily spend − ₹3


Concept / Approach:
Form the equation 360/(n + 4) = 360/n − 3 and solve for n. This is a rational equation leading to a quadratic that factors cleanly.


Step-by-Step Solution:
360/(n + 4) = 360/n − 3Multiply by n(n + 4): 360n = (n + 4)(360 − 3n)Expand: 360n = 360n − 3n^2 + 1440 − 12nRearrange: 3n^2 + 12n − 1440 = 0 → n^2 + 4n − 480 = 0Solve: n = [−4 + √(16 + 1920)] / 2 = (−4 + 44)/2 = 20


Verification / Alternative check:
Old daily = 360/20 = ₹18; new daily = 360/24 = ₹15; drop is ₹3, which matches.


Why Other Options Are Wrong:
15, 16, 18, 24 do not satisfy the exact ₹3 reduction when checked back with 360/n and 360/(n+4).


Common Pitfalls:
Sign slips while expanding or canceling 360n prematurely. Keep terms aligned before simplifying.


Final Answer:
20

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