Difficulty: Easy
Correct Answer: irreversible
Explanation:
Introduction / Context:Throttling (Joule–Thomson) is a flow through a restriction such as a valve or porous plug with a significant pressure drop and negligible shaft work and heat transfer. It is ubiquitous in refrigeration, natural gas pressure letdown, and control valves.
Given Data / Assumptions:
Concept / Approach:Throttling is inherently dissipative because of viscous/frictional effects and non-equilibrium within the restriction. Entropy increases across the valve, and the process cannot be reversed without additional work input and reorganization. Enthalpy remains approximately constant (h1 ≈ h2) for ideal throttling, but irreversibility is indicated by Δs > 0 for most fluids.
Step-by-Step Solution:
Model device as adiabatic with no shaft work.Energy equation reduces to h1 ≈ h2 (neglecting KE/PE changes).Recognize strong internal friction and mixing → entropy generation.Conclude process is irreversible.Verification / Alternative check:On an h–p diagram, throttling follows an isenthalpic line with a rise in entropy for typical fluids at moderate pressures, confirming irreversibility.
Why Other Options Are Wrong:
Common Pitfalls:Confusing “adiabatic and no shaft work” with “reversible”; adiabatic does not imply reversible.
Final Answer:irreversible
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