Three states X, Y, and Z had students appearing for an exam in 1998 in the ratio 3 : 5 : 6. Next year, the numbers rose by 20%, 10%, and 20% respectively. If in the next year the ratio of students in states X and Z is 1 : 2, determine whether the 1998 numbers can be uniquely found.

Difficulty: Easy

Correct Answer: Data is insufficient

Explanation:


Introduction / Context:
This is a data sufficiency style question disguised as a percentage/ratio problem. We are asked whether the original numbers (1998) can be uniquely determined using the given ratios and percentage changes.


Given Data / Assumptions:

  • 1998 ratio X : Y : Z = 3 : 5 : 6 ⇒ numbers = 3k, 5k, 6k.
  • Next year increases: X by 20%, Y by 10%, Z by 20%.
  • Next year X : Z is 1 : 2.


Concept / Approach:
Compute next-year values as factors of k and check the X : Z ratio. If the ratio condition holds identically (for all k), then k is not determined and original totals cannot be uniquely fixed.


Step-by-Step Solution:

Next year X = 3k * 1.20 = 3.6kNext year Z = 6k * 1.20 = 7.2kTheir ratio = 3.6k : 7.2k = 1 : 2 (since both sides divide by 3.6k)The ratio holds for any k, so k is not pinned down.


Verification / Alternative check:
Even if Y’s growth is included, it doesn’t affect the X : Z ratio. Without an absolute count or another independent equation, 1998 totals are undetermined.


Why Other Options Are Wrong:
Numerical totals (5000, 6000, 75000, 7000) cannot be justified uniquely from the data.


Common Pitfalls:
Assuming ratios alone can produce exact totals; missing that a free scale factor k remains.


Final Answer:
Data is insufficient

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