Of the three numbers, the sum of the first two is 73; the sum of the second and the third is 77 and the sum of the third and thrice the first is 104. The third number is

Aptitude Problems on Numbers Difficulty: Medium
Choose an option
  • A
    25
  • B
    39
  • C
    48
  • D
    Cannot be determined
  • E
    None of these

Answer

Correct Answer: None of these

Explanation

### Concept & Strategy This requires solving a system of three linear equations. The fastest approach is to eliminate variables by subtracting equations that share a common term. ### Step-by-Step Solution * **Given:** Let the numbers be $x$, $y$, and $z$. Eq 1: $x + y = 73$ Eq 2: $y + z = 77$ Eq 3: $z + 3x = 104$ * **Calculation:** Subtract Eq 1 from Eq 2 to eliminate $y$. $(y + z) - (x + y) = 77 - 73$ $z - x = 4 \implies z = x + 4$ * Substitute this expression for $z$ into Eq 3. $(x + 4) + 3x = 104$ $4x + 4 = 104$ $4x = 100 \implies x = 25$ * **Deduction:** Now, substitute $x = 25$ back into our expression for $z$. $z = 25 + 4 = 29$ The first number is $25$, the second is $48$, and the third is $29$. Since $29$ is not listed among the first three options, the correct choice is "None of these". ### Exam Strategy & Shortcut Instead of finding all three variables, strictly focus on the target. You need $z$. From $x + y = 73$ and $y + z = 77$, the difference is clearly $z - x = 4$. Rearranging gives $x = z - 4$. Substitute into $z + 3x = 104$: $z + 3(z - 4) = 104 \implies 4z - 12 = 104 \implies 4z = 116 \implies z = 29$. This prevents calculating unneeded variables. ### Common Pitfall A common trap is solving for the first variable ($x = 25$) and accidentally selecting option (a) because it matches, completely forgetting that the question specifically asks for the *third* number. Always reread the final prompt. ### Final Answer **Therefore, the correct answer is None of these.**
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