Profit and Loss – Prices of three cars in ratio 4 : 5 : 7: The ratio of the prices of three different cars is 4 : 5 : 7. If the difference between the costliest and the cheapest is Rs 60000, what is the price of the car with the middle price?

Introduction / Context:
This is a direct ratio problem. When three values are in a fixed ratio, differences correspond to multiples of the common scaling factor. Use the given rupee difference to determine that factor, then compute the middle price.

Given Data / Assumptions:

• Price ratio = 4 : 5 : 7
• Difference between highest and lowest = Rs 60000

Concept / Approach:
Let prices be 4x, 5x, and 7x. Then 7x − 4x = 3x = 60000 ⇒ x = 20000. The middle price is 5x.

Step-by-Step Solution:
3x = 60000 ⇒ x = 20000Middle price = 5x = 5 * 20000 = Rs 100000

Verification / Alternative check:
Lowest = 80000; highest = 140000; difference = 60000 as stated.

Why Other Options Are Wrong:
80000 and 120000 are the extreme prices, not the middle; 140000 is the highest; 90000 is not aligned with the ratio.

Common Pitfalls:
Using average instead of ratio scaling; always apply the common factor method.

Final Answer:
Rs 1,00,000