Series inductance calculation: Three inductors of 15 mH each are connected in series. What is the total inductance?

Difficulty: Easy

Correct Answer: 45 mH

Explanation:


Introduction / Context:
Inductors in series add directly, similar to resistors in series. This provides a simple way to obtain a higher total inductance for filters, chokes, and timing networks.


Given Data / Assumptions:

  • Three inductors, each 15 mH.
  • All three are connected in series.
  • Ideal components with negligible coupling.


Concept / Approach:

For series inductors (with negligible mutual coupling), L_total = L1 + L2 + L3. Units must be consistent (millihenry here).


Step-by-Step Solution:

L_total = 15 mH + 15 mH + 15 mH = 45 mH.


Verification / Alternative check:

If series inductors had coupling, mutual inductance M terms would affect the result. With ideal, un-coupled coils, simple addition applies.


Why Other Options Are Wrong:

30 mH implies only two coils added. 15 mH implies one coil. 5 mH is unrelated to series addition.


Common Pitfalls:

Confusing series with parallel behavior; ignoring mutual coupling in real layouts (not part of this ideal problem).


Final Answer:

45 mH

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