Identify Thevenin vs. Norton: Thevenin’s theorem reduces any linear AC circuit to an equivalent current source in parallel with an equivalent impedance. True or false?

Difficulty: Easy

Correct Answer: False

Explanation:


Introduction / Context:
Thevenin and Norton theorems provide dual, interchangeable equivalents for linear circuits. Knowing which is which prevents modeling mistakes when simplifying networks for load analysis or maximum power transfer problems.



Given Data / Assumptions:

  • The circuit is linear and bilateral over the range of interest.
  • Dependent sources are allowed if properly handled when finding equivalents.
  • Frequency-domain AC analysis uses complex impedances.


Concept / Approach:

Thevenin equivalent: a single voltage source in series with an equivalent impedance (Vth in series with Zth). Norton equivalent: a single current source in parallel with an equivalent impedance (In in parallel with Zn). The two are related by source transformation: Vth = In * Zth and Zth = Zn.



Step-by-Step Solution:

Find Vth: open-circuit the load and compute the terminal voltage.Find Zth: zero independent sources (voltage sources → short, current sources → open) and compute equivalent impedance seen at the terminals (or use Voc/Isc).Form Thevenin model: Vth in series with Zth. This is not a current source.


Verification / Alternative check:

Compute the short-circuit current Isc. Then In = Isc for the Norton model and Vth = In * Zth; both models predict identical load currents and voltages for any load, confirming duality.



Why Other Options Are Wrong:

  • Choosing “True” confuses Norton with Thevenin. A current source in parallel corresponds to Norton, not Thevenin.


Common Pitfalls:

Mixing up the required test condition: open-circuit for Vth, short-circuit for In. Also, incorrectly deactivating dependent sources when finding Zth—use a test source method if dependents exist.


Final Answer:

False

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