Thermal (slow) neutrons at 0.025 eV: estimate the typical speed of such neutrons in metres per second for reactor physics calculations.
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A1100
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B2200
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C3300
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D4400
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E1500
Answer
Correct Answer: 2200
Explanation
Introduction / Context:In thermal reactors, neutron speeds at room temperature are often approximated for quick calculations and intuition. A widely used reference energy is 0.025 eV, corresponding to standard “thermal” conditions near 20–25 °C.
Given Data / Assumptions:
- Neutron kinetic energy E ≈ 0.025 eV representative of room-temperature thermal neutrons.
- We need an order-of-magnitude speed used in hand calculations.
- Non-relativistic kinetic energy relation applies.
Concept / Approach:For non-relativistic particles, E = (1/2) * m * v^2. Using E ≈ 0.025 eV and neutron mass m_n, the commonly memorized result is v ≈ 2200 m/s (more precisely ~2200 m/s at 20 °C). This becomes a standard constant used in cross-section-to-reaction-rate conversions at “2200 m/s” reference conditions in many nuclear data libraries.
Step-by-Step Solution:Recall thermal reference: E_ref ≈ 0.025 eV.Use the standard tabulated equivalence: E_ref ↔ v ≈ 2200 m/s.Select 2200 as the typical value.
Verification / Alternative check:Detailed calculation with constants (converting eV to joules and inserting neutron mass) yields a velocity close to 2.2 * 10^3 m/s, confirming the memorized figure.
Why Other Options Are Wrong:
- 1100, 3300, 4400, 1500: Not the standard reference velocity for 0.025 eV; 2200 m/s is the accepted benchmark.
Common Pitfalls:Forgetting that “thermal” is a temperature-dependent distribution; 2200 m/s is a convenient reference, not a unique speed for all thermal neutrons.
Final Answer:2200