Heat conduction in solids – Dependence of thermal conductivity For a conducting solid material (e.g., metals, ceramics, porous refractories), thermal conductivity may vary with which intrinsic or structural factors? Identify the best choice.
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Atemperature
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Bporosity
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Cboth (a) & (b)
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Dneither (a) nor (b)
Answer
Correct Answer: both (a) & (b)
Explanation
Introduction / Context:Thermal conductivity k is not necessarily constant. In real solids, k often depends on temperature (phonon and electron transport effects) and on microstructure, including porosity. Recognizing these dependencies is important for furnace linings, insulation, and high-temperature equipment design.
Given Data / Assumptions:
- Homogeneous solid whose microstructure may include pores.
- Steady-state, one-dimensional conduction concepts apply.
- Temperature range may affect carriers (phonons/electrons).
Concept / Approach:In metals, electron scattering increases with temperature, often reducing k at high T; in many ceramics, phonon scattering changes so k can decrease with T over practical ranges. Porosity introduces low-conductivity gas-filled regions and tortuous paths, decreasing effective k. Therefore, both temperature and porosity influence k in practice.
Step-by-Step Solution:
Assess temperature dependence of carriers (electrons/phonons) ⇒ k varies with T.Consider microstructure; pores interrupt heat paths ⇒ lower effective k.Conclude that both temperature and porosity matter.Choose the combined option (a) & (b).Apply this understanding in selecting materials for insulation vs heat sinks.Verification / Alternative check:Handbooks list k(T) curves; porous firebricks show order-of-magnitude lower k than dense ceramics at the same temperature.
Why Other Options Are Wrong:
- Single-factor options ignore well-documented dependencies.
- “Neither” contradicts extensive experimental data.
Common Pitfalls:Using constant-k assumptions outside narrow temperature ranges; for accuracy, incorporate k(T) and porosity corrections in design calculations.
Final Answer:both (a) & (b)